Recall the formula of the rms speed of a molecule of gas and the ideal gas equation.
The kinetic energy of the gas is given by
\(K =\frac{1}{2} mv _{ rms }^{2}\)
Where
\(R m s\) velocity of gas molecules is given by
\(v _{ rms }=\sqrt{\frac{3 R T}{m}}\)
Where
\(\therefore K =\frac{1}{2} m \cdot \frac{3 RT }{ m }=\frac{3}{2} RT\)
From the ideal gas equation, \(RT = PV\)
\(\Rightarrow K =\frac{3}{2} PV\)
Thus we get the pressure of the gas \(P =\frac{2}{3} \frac{ K }{ V }\)
Therefore, the pressure exerted by the gas on the walls of the container is \([\frac{2}{3}]^{rd}\) kinetic energy per unit volume of a gas.
Discover More from Chapter: Kinetic Theory of Gases
The Correct Answer is (B)
1. Due to the collision of the air molecules with the walls of the tire results in the pressure of the air in a tire.
2. The pressure of water in a dam is caused by the weight of the water.
3. The pressure of blood in arteries is caused by the heart.
4. The pressure of the atmosphere is caused by the weight of the air.
1. What is the relationship between pressure and the number of gas molecules?
2. How does the pressure of a gas change with the volume of the container?
3. What is the effect of temperature on the pressure of a gas?
The Correct Answer is (B)
According to the Kinetic theory of gases
The pressure exerted by an ideal gas is given by the formula
\(P=\frac{1}{3}\frac{M}{V}v^2\)
Where
The motion of a particle in the XY plane is given by \( x(t) = 25 + 6t^2 \, \text{m} \); \( y(t) = -50 - 20t + 8t^2 \, \text{m} \). The magnitude of the initial velocity of the particle, \( v_0 \), is given by: