Question:
Assuming fully decomposed, the volume of \( {CO}_2 \) released will be:
Assuming fully decomposed, the volume of \( {CO}_2 \) released will be:
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At STP, 1 mole of any ideal gas occupies 22.4L. Use this to calculate the volume of gases in reactions.
Updated On: Feb 13, 2025
- 1.12L
- 2.24L
- 4.06L
- 0.84L
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The Correct Option is A
Solution and Explanation
Step 1: To determine the volume of \( {CO}_2 \) released, we need to know the reaction that releases the gas and its stoichiometry. Assume we are dealing with a complete decomposition reaction where 1 mole of a compound like calcium carbonate (CaCO₃) decomposes to release 1 mole of \( {CO}_2 \).
Step 2: According to the ideal gas law at standard conditions (STP), 1 mole of any ideal gas occupies 22.4L.
Step 3: In the case of 1 mole of \( {CO}_2 \), the volume will be 22.4L. However, for the given amount of the compound (assuming it's 1/20th of a mole), the volume of \( {CO}_2 \) will be: \[ {Volume of CO}_2 = \frac{22.4L}{20} = 1.12L \] Therefore, the volume of \( {CO}_2 \) released is 1.12L.
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