For a first-order reaction, the half-life (\(t_{1/2}\)) is given by the formula:
\[
t_{1/2} = \frac{0.693}{k}
\]
Given:
- Rate constant \(k = 0.01 \, \text{s}^{-1}\)
Step 1: Calculate the half-life
\[
t_{1/2} = \frac{0.693}{0.01} = 69.3 \, \text{s}
\]
Answer: Therefore, the half-life of the reaction is \(69.3 \, \text{s}\), and the correct answer is option (1).