Surface Area of Cube = 6 × Sides2
= 6 × 102
= 6 × 100
= 600
\(\text{Paint required} = \frac{\text{Surface Area Of Cube}}{\text{1 kg paint Area}}\)
= \(\text{Paint required} = \frac{600}{15}\)
\(Paint Required\) = \(40 kg\)
Cost Of Paint = \(40 kg \times 60 \frac{rupees}{kg}\)
= 2400 rupees
The correct option is (C): 2400