The general equation of a circle with constant radius \( r \) is: \[ (x - a)^2 + (y - b)^2 = r^2 \] This has two arbitrary constants: \( a \) and \( b \) (the center coordinates).
Differentiating twice is required to eliminate both constants and obtain a differential equation, which makes the order 2.
So Assertion (A) is true.
Now, Reason (R) states:
> An algebraic equation having two arbitrary constants represents the general solution of a second-order differential equation.
This is correct and directly explains why the order is 2.
Thus, both A and R are true, and R is the correct explanation of A.
Let \( y = y(x) \) be the solution of the differential equation \[ \frac{dy}{dx} + 2y \sec^2 x = 2 \sec^2 x + 3 \tan x \cdot \sec^2 x \] such that \( y(0) = \frac{5}{4} \). Then \[ 12 \left( y\left( \frac{\pi}{4} \right) - e^{-2} \right) \] is equal to _____.
For the curve \( \sqrt{x} + \sqrt{y} = 1 \), find the value of \( \frac{dy}{dx} \) at the point \( \left(\frac{1}{9}, \frac{1}{9}\right) \).