Using Boolean algebra identity:
\[
(A + B)(A + C) = A + BC
\]
Proof:
Expand using distributive law:
\[
(A + B)(A + C) = AA + AC + AB + BC = A + AC + AB + BC
\]
But in Boolean algebra:
$AA = A$
$A + AC = A$
$A + AB = A$
So,
\[
A + AC + AB + BC = A + BC
\]
Therefore, (A + B)(A + C) = A + BC
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