Question:

Arrange the following states in the descending order of their population density as per Census of India, 2011:
(A) West Bengal
(B) Uttar Pradesh
(C) Kerala
(D) Tamil Nadu

Updated On: May 14, 2025
  • (D), (A), (B), (C)
  • (A), (C), (B), (D)
  • (B), (A), (D), (C)
  • (A), (B), (D), (C)
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The Correct Option is B

Approach Solution - 1

To solve this question, we need to arrange the states based on their population density according to the Census of India, 2011. Population density is defined as the number of people per square kilometer.

StatePopulation Density (people/km²)
West Bengal1029
Uttar Pradesh828
Kerala859
Tamil Nadu555

Based on the population densities:

  • West Bengal: 1029 people/km²
  • Kerala: 859 people/km²
  • Uttar Pradesh: 828 people/km²
  • Tamil Nadu: 555 people/km²

Thus, the correct order is: (A), (C), (B), (D)

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Approach Solution -2

As per the Census of India 2011, the population density of states in descending order is as follows:

  • West Bengal (A): West Bengal has a high population density, making it the most densely populated state among the options.
  • Kerala (C): Kerala also has a very high population density, though slightly lower than West Bengal.
  • Uttar Pradesh (B): Uttar Pradesh is the most populous state in India, but its population density is somewhat lower than Kerala and West Bengal.
  • Tamil Nadu (D): Tamil Nadu has a relatively high population density but is lower than Uttar Pradesh.

Thus, the correct order of population density (from highest to lowest) is West Bengal, Kerala, Uttar Pradesh, and Tamil Nadu, which matches option (B) (A), (C), (B), (D).

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