The basic character of amines depends on the availability of the lone pair of electrons on the nitrogen atom, which can donate to a proton (H⁺) in the gaseous phase. The alkyl groups attached to nitrogen increase the basicity by donating electron density through the inductive effect, thus making the lone pair on nitrogen more available for protonation.
- NH₃ (Ammonia): Ammonia has no alkyl groups and has the least electron donation effect, so it is the least basic.
- CH₃NH₂ (Methylamine): The methyl group (CH₃) donates electron density to the nitrogen, increasing the availability of the lone pair, making methylamine more basic than ammonia.
- (CH₃)₂NH (Dimethylamine): The presence of two methyl groups increases electron density on nitrogen even more, making dimethylamine more basic than methylamine.
- (CH₃)₃N (Trimethylamine): The three methyl groups donate the most electron density, making trimethylamine the most basic among the amines listed.
Thus, the order of basicity in the gaseous phase is: (CH₃)₃N>(CH₃)₂NH>CH₃NH₂>NH₃.
Therefore, the correct answer is Option (2).