Question

Arrange products formed during payoff phase of the six-carbon glucose breakdown in correct sequence.
(A) 3-Phosphoglycerate
(B) Glyceraldehyde 3-phosphate
(C) Phosphoenolpyruvate
(D) 1,3-Bisphosphoglycerate

• A. (A), (C), (B), (D)
• B. (C), (B), (D), (A)
• C. (D), (A), (C), (B)
• D. (B), (D), (A), (C)
• E.

Hint:

In the payoff phase of glycolysis, high-energy intermediates are produced which contribute to ATP formation.

Answer 1

The Correct Option is A

Step 1: Breakdown of glucose.
The breakdown of six-carbon glucose to two molecules of pyruvate occurs during glycolysis.
During the payoff phase, ATP is produced, and key intermediates are formed.
Step 2: Correct sequence of intermediates.
- (A) 3-Phosphoglycerate: This is formed after ATP is used to convert 1,3-bisphosphoglycerate into 3-phosphoglycerate.
- (C) Phosphoenolpyruvate: This is formed from 2-phosphoglycerate by the action of enolase, and later it is converted to pyruvate.
- (B) Glyceraldehyde 3-phosphate: This is a product of the splitting of fructose-1,6-bisphosphate and is involved in further ATP production.
- (D) 1,3-Bisphosphoglycerate: This is formed after glyceraldehyde 3-phosphate undergoes oxidation.
Step 3: Conclusion.
Thus, the correct sequence of intermediates is (A), (C), (B), (D).