1. Understand Acidity and Hybridization
The acidity of a C-H bond is related to the stability of the resulting carbanion after deprotonation (removal of the proton). The stability of the carbanion is, in turn, influenced by the hybridization of the carbon atom bearing the negative charge. A higher s-character in the hybrid orbital leads to greater electronegativity of the carbon, thus stabilizing the carbanion.
- sp hybridization: 50% s-character
- sp2 hybridization: 33.3% s-character
- sp3 hybridization: 25% s-character
Therefore, the order of acidity based on hybridization is: sp > sp2 > sp3.
2. Determine the hybridization of carbon atoms in the given compounds
- Ethyne (Acetylene, HC≡CH): The carbon atoms are sp hybridized. The hydrogen atoms are directly attached to sp hybridized carbons, making it acidic.
- Benzene (C6H6): The carbon atoms are sp2 hybridized. Benzene is less acidic than ethyne because sp2 hybridized carbon is less electronegative than sp hybridized carbon.
- n-Hexane (C6H14): The carbon atoms are sp3 hybridized. n-Hexane is the least acidic among the three because the sp3 hybridized carbon is the least electronegative.
3. Arrange in decreasing order of acidic behavior
Based on the hybridization, the decreasing order of acidity is:
Ethyne > Benzene > n-Hexane
4. Compare with the given options
Comparing the derived order with the options, we find that it matches option (D).
Final Answer:
(D) ethyne > Benzene > n-hexane
To compare the acidic behavior of benzene, n-hexane, and ethyne, we look at their ability to donate protons (H⁺):
The correct answer is (D) : ethyne > Benzene > n-hexane.
Complete the following equation :
Write the products of the following reactions:
Predict the major product $ P $ in the following sequence of reactions:
(i) HBr, benzoyl peroxide
(ii) KCN
(iii) Na(Hg), $C_{2}H_{5}OH$