The work done \( W \) in moving a charge in an electric field is given by: \[ W = q \cdot V \] where \( q \) is the charge being moved and \( V \) is the potential at the point where the charge is located. In this case, the charge is being moved in a circular path around a stationary charge.
Since the stationary charge is fixed, the electric potential around it is constant for any circular path around it.
Therefore, there is no change in potential as the charge moves around the circle. Since the electric potential remains constant, the work done in moving the charge is zero.
The correct option is (C) : zero
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: