>
Exams
>
Aptitude
>
Aptitude Mixed
>
architect of sydney opera house
Question:
Architect of Sydney Opera House?
JEE Main - 2024
JEE Main
Updated On:
Jan 13, 2026
Hide Solution
Verified By Collegedunia
Solution and Explanation
The answer is Jørn Obreg Utzon.
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on Aptitude Mixed
From the given options, choose the correct one that will replace the question mark (?) in the following series:
2, 0, 3, 2, 4, 6, 5, 12, 6, ?, 7, 30
VITEEE - 2025
Aptitude
Aptitude Mixed
View Solution
Select the number from among the given options that can replace the question mark (?) in the following series:
3, 10, 24, ?, 73, 108
VITEEE - 2025
Aptitude
Aptitude Mixed
View Solution
Stone-cut chariot wheel cravings are from which temple?
JEE Main - 2024
Aptitude
Aptitude Mixed
View Solution
Elephanta caves show which god?
JEE Main - 2024
Aptitude
Aptitude Mixed
View Solution
What is full form of LEED ?
JEE Main - 2024
Aptitude
Aptitude Mixed
View Solution
View More Questions
Questions Asked in JEE Main exam
In an experiment, a set of readings are obtained as follows: \[ 1.24~\text{mm},\ 1.25~\text{mm},\ 1.23~\text{mm},\ 1.21~\text{mm}. \] The expected least count of the instrument used in recording these readings is _______ mm.
JEE Main - 2026
General Physics
View Solution
Method used for separation of mixture of products (B and C) obtained in the following reaction is:
JEE Main - 2026
p -Block Elements
View Solution
The number of numbers greater than $5000$, less than $9000$ and divisible by $3$, that can be formed using the digits $0,1,2,5,9$, if repetition of digits is allowed, is
JEE Main - 2026
Permutations
View Solution
Two point charges of \(1\,\text{nC}\) and \(2\,\text{nC}\) are placed at two corners of an equilateral triangle of side \(3\) cm. The work done in bringing a charge of \(3\,\text{nC}\) from infinity to the third corner of the triangle is ________ \(\mu\text{J}\). \[ \left(\frac{1}{4\pi\varepsilon_0}=9\times10^9\,\text{N m}^2\text{C}^{-2}\right) \]
JEE Main - 2026
Electrostatics
View Solution
Evaluate: \[ \frac{6}{3^{26}}+\frac{10\cdot1}{3^{25}}+\frac{10\cdot2}{3^{24}}+\frac{10\cdot2^{2}}{3^{23}}+\cdots+\frac{10\cdot2^{24}}{3}. \]
JEE Main - 2026
Integral Calculus
View Solution
View More Questions