Question:
Aqueous solution of $Na_2S_2O_3$ on reaction with $Cl_2$ gives
Aqueous solution of $Na_2S_2O_3$ on reaction with $Cl_2$ gives
Updated On: Aug 1, 2023
- $Na_2S_4O_6$
- $NaHSO_4$
- $NaCl$
- $NaOH$
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The Correct Option is B
Approach Solution - 1
Sodium thiosulphate, $Na_2S_2O_3$ gets oxidised by chlorine
water as $Na_2S2O_3 + 4Cl_2 + 5 H_2O \longrightarrow 2NaHSO_4 + 8HCl$
$FeCl_3 oxidises Na_2S_2O_3 to Na_2S_4O_6$
water as $Na_2S2O_3 + 4Cl_2 + 5 H_2O \longrightarrow 2NaHSO_4 + 8HCl$
$FeCl_3 oxidises Na_2S_2O_3 to Na_2S_4O_6$
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Approach Solution -2
Oxidation is the loss of electrons during a chemical reaction. The molecule that helps in the oxidation process is the oxidising agent and the molecule that gets oxidised acts as a reducing agent.
When Na₂S₂O₃ reacts with Cl₂, it gets oxidised. The reaction for the same is as follows:
Na₂S₂O₃ +4Cl+ 5H₂O →2NaHSO₄ + 8HCl
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- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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