Comprehension
Answer the questions based on the information given below The Venn diagram given below shows the estimated readership of 3 daily newspapers (X, Y & Z) in a city. The total readership and advertising cost for each of these papers is as below
NewspapersReadership (lakhs)Advertising cost
(Rs. per sq. cm)
X8.76000
Y9.16500
Z5.65000
The total population of the city is estimated to be 14 million. The common readership (in lakhs) is indicated in the given Venn diagram
 Venn diagram
Question: 1

The number of people (in lakhs) who read at least one newspaper is

Updated On: Aug 21, 2025
  • 4.7
  • 11.9
  • 17.4
  • 23.4
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The Correct Option is C

Solution and Explanation

Given data (in lakhs):
• Readership totals: |X| = 8.7, |Y| = 9.1, |Z| = 5.6.
• Venn (pairwise-only & triple): X∩Y only = 2.5, Y∩Z only = 1.5, X∩Z only = 1.0, and X∩Y∩Z = 0.5.

Step 1 — Express each paper’s total as disjoint regions:
|X| = (only X) + (X∩Y only) + (X∩Z only) + (X∩Y∩Z).
|Y| = (only Y) + (X∩Y only) + (Y∩Z only) + (X∩Y∩Z).
|Z| = (only Z) + (X∩Z only) + (Y∩Z only) + (X∩Y∩Z).

Step 2 — Solve for “only” regions using the totals:
only X = 8.7 − (2.5 + 1.0 + 0.5) = 8.7 − 4.0 = 4.7.
only Y = 9.1 − (2.5 + 1.5 + 0.5) = 9.1 − 4.5 = 4.6.
only Z = 5.6 − (1.0 + 1.5 + 0.5) = 5.6 − 3.0 = 2.6.

Step 3 — Compute “at least one” (= union) by adding all disjoint regions:
|X ∪ Y ∪ Z| = (only X) + (only Y) + (only Z) + (X∩Y only) + (Y∩Z only) + (X∩Z only) + (X∩Y∩Z).
= 4.7 + 4.6 + 2.6 + 2.5 + 1.5 + 1.0 + 0.5.
Add sequentially for clarity:
4.7 + 4.6 = 9.3 → 9.3 + 2.6 = 11.9 → 11.9 + 2.5 = 14.4 → 14.4 + 1.5 = 15.9 → 15.9 + 1.0 = 16.9 → 16.9 + 0.5 = 17.4.

Step 4 — Quick inclusion–exclusion check (conceptual):
When pairwise entries are “only” overlaps, the union is simply the sum of all seven disjoint regions; that’s exactly what we computed above, confirming no double counting.

Final Answer: 17.4 lakhs (matches option (C)).
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Question: 2

The number of people (in lakhs) who read only one newspaper is

Updated On: Aug 21, 2025
  • 4.7
  • 11.9
  • 17.4
  • 23.4
Hide Solution
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The Correct Option is B

Solution and Explanation

Goal: Find the number of people (in lakhs) who read only one of the newspapers X, Y, Z.

Given (from the Venn and table, all in lakhs):
|X| = 8.7, |Y| = 9.1, |Z| = 5.6.
X∩Y only = 2.5, Y∩Z only = 1.5, X∩Z only = 1.0, X∩Y∩Z = 0.5.

Step 1 — Express totals as disjoint-region sums:
|X| = (only X) + (X∩Y only) + (X∩Z only) + (X∩Y∩Z).
|Y| = (only Y) + (X∩Y only) + (Y∩Z only) + (X∩Y∩Z).
|Z| = (only Z) + (X∩Z only) + (Y∩Z only) + (X∩Y∩Z).

Step 2 — Solve the “only” regions:
only X = 8.7 − (2.5 + 1.0 + 0.5) = 8.7 − 4.0 = 4.7.
only Y = 9.1 − (2.5 + 1.5 + 0.5) = 9.1 − 4.5 = 4.6.
only Z = 5.6 − (1.0 + 1.5 + 0.5) = 5.6 − 3.0 = 2.6.

Step 3 — Add the exactly-one readers:
Total (only one) = (only X) + (only Y) + (only Z) = 4.7 + 4.6 + 2.6 = 11.9 lakhs.

Answer: 11.9 lakhs (matches option (B)).
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