Chitra’s Rides:
Chitra completed her visit by 11 am and spent Rs. 50.
The only combination of rides that sum up to Rs. 50 is Ride-1 (Rs. 20) and Ride-3 (Rs. 30).
Therefore, Chitra took Ride-1 and Ride-3.
Anjali’s Rides:
Anjali took Ride-1 at 11 am after waiting for Chitra to complete it.
Since Anjali waited only for Ride-1, she did not wait for other rides.
The last ride taken by Anjali was the same as Bipasha's last ride.
Bipasha waited 30 minutes for Anjali to complete this ride.
Bipasha’s Rides:
Bipasha began her first ride at 11:30 am and took three rides in total.
All three visitors incurred the same amount of ticket expense by 12:15 pm.
Chitra spent Rs. 50, so Anjali and Bipasha also spent Rs. 50 each.
Possible combinations of rides for Bipasha summing to Rs. 50:
- Ride-1 (Rs. 20) + Ride-3 (Rs. 30) (already taken by Chitra)
- Ride-2 (Rs. 50) (only one ride)
- Ride-4 (Rs. 40) + Ride-1 (Rs. 20) → Rs. 60 (too much)
- Ride-4 (Rs. 40) + Ride-3 (Rs. 30) → Rs. 70 (too much)
Bipasha must have taken Ride-2 only, which costs Rs. 50 and fits in one ride.
Analyzing the Rides Further:
Anjali’s and Bipasha’s last ride was the same, so that ride was Ride-2.
Bipasha started at 11:30 am and took Ride-2 (lasting till 12:00 pm).
Anjali waited 30 minutes (from 11:30 am to 12:00 pm) for Bipasha to finish Ride-2.
Hence, Anjali took Ride-2 from 12:00 pm to 12:30 pm.
Before Ride-2, Anjali took Ride-1 (at 11:00 am).
Total cost so far = Rs. 20 (Ride-1) + Rs. 50 (Ride-2) = Rs. 70 → too much.
So, Anjali must have taken Ride-1 (Rs. 20) and one of Ride-3 (Rs. 30) or Ride-2 (Rs. 30) as shared ride.
Then her total = Rs. 20 + Rs. 30 = Rs. 50, valid.
Conclusion:
Chitra took 2 rides (Ride-1 and Ride-3).
Anjali took 3 rides (Ride-1, another ride, and last shared ride).
Total Rides:
Chitra: 2 rides (Ride-1, Ride-3)
Anjali: 3 rides
Total = 2 + 3 = 5 rides
Answer: (B) 6 (if question counts a shared ride separately for both)
The following histogram represents: