Due to salt formation with AlCl\(_3\), aniline becomes a Lewis base, deactivating the benzene ring.
Step 1: Role of Lewis Acid Catalyst in Friedel-Crafts Reaction - Friedel-Crafts alkylation and acylation require a Lewis acid catalyst like AlCl\(_3\) to generate the electrophile.
Step 2: Interaction Between Aniline and AlCl\(_3\) - Aniline (\( \text{C}_6\text{H}_5\text{NH}_2 \)) has a lone pair on nitrogen, which interacts with AlCl\(_3\), forming a salt. \[ \text{C}_6\text{H}_5\text{NH}_2 + AlCl_3 \rightarrow [\text{C}_6\text{H}_5\text{NH}_2]^+ [AlCl_3]^- \] - This deactivates the benzene ring, making it less reactive toward electrophilic substitution.
Step 3: Conclusion Due to this salt formation, aniline does not undergo Friedel-Crafts reaction.
Match List-I with List-II for the following reaction pattern: \[ \text{Glucose} \quad \text{Reagent} \quad \rightarrow \quad \text{Product} \quad \rightarrow \quad \text{Structural prediction} \]
Which of the following is not an aromatic compound?
Among the following, identify the compound that is not an isomer of hexane:
Chlorobenzene reacts with bromine gas in the presence of Anhydrous AlBr_3 to yield p-Bromochlorobenzene. This reaction is classified as
The correct IUPAC name of \([ \text{Pt}(\text{NH}_3)_2\text{Cl}_2 ]^{2+} \) is: