Question:

Anil can paint a house in 12 days while Barun can paint it in 16 days. Anil, Barun, and Chandu undertake to paint the house for ₹ 24000 and the three of them together complete the painting in 6 days. If Chandu is paid in proportion to the work done by him, then the amount in INR received by him is

Updated On: Apr 20, 2024
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Approach Solution - 1

Let's first determine the work rates for Anil and Barun.

Anil's work rate is 112\frac{1}{12} of the house per day since he can complete painting the house in 12 days.
Similarly, Barun's work rate is 116\frac{1}{16} of the house per day. When Anil, Barun, and Chandu work together, they complete the house in 6 days.

So, their combined work rate is 16\frac{1}{6} of the house per day.

Given the work rates for Anil and Barun:
Anil+Barun+Chandu=16Anil + Barun + Chandu = \frac{1}{6}

Substituting in the known rates:
112+116+Chandu=16\frac{1}{12} + \frac{1}{16} + Chandu = \frac{1}{6}

Finding the least common denominator, which is 48: 4+3+48×Chandu=84 + 3 + 48 \times Chandu = 8
48×Chandu=148 \times Chandu = 1
Chandu=148Chandu = \frac{1}{48}

This means Chandu's work rate is 148\frac{1}{48} of the house per day.

Over 6 days, Chandu would have completed: 

6×148=186 \times \frac{1}{48} = \frac{1}{8} or 12.5% of the house.

So, Chandu's share of the payment is 12.5% of ₹24000:
0.125×24000=30000.125 \times 24000 = ₹3000 
So, Chandu will receive ₹3000.

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Approach Solution -2

Given that, Anil can paint a house in 1212 days while Barun can paint it in 1616 days.
Now, Arun, Barun and Chandu painted  together in 66 Days.
Now, let total work be WW and each worked for 66 days.
Then, Anil's work =0.5W= 0.5W
Barun's work =6W16= \frac {6W}{16}=3W8= \frac {3W}{8}
Hence, Charu's work = W23W8=W8\frac W2- \frac {3W}{8} = \frac W8
Then the amount received by Chandu,
==240008\frac {24000}{8}
=Rs. 3000= Rs.\ 3000

So, the answer is Rs. 3000Rs.\ 3000.

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