The sum of the measures of all interior angles of a triangle is \(180\degree\).
\(\angle PQR + \angle PRQ + \angle QPR = 180\degree\)
\(25\degree + 65\degree + \angle QPR = 180\degree\)
\(90\degree + \angle QPR = 180\degree\)
\(\angle QPR = 180\degree - 90\degree = 90\degree\)
Therefore, \(Δ\) \(PQR\) is right-angled at point \(P\).
Hence, \((PR)^2 + (PQ)^2= (QR)^2\)
Thus, (ii) is true.