The energy of the emitted photon is:
\[E = 0.05 \times \text{eV} = 0.05 \times (20 \, \text{kV})\]
Using \(E = \frac{hc}{\lambda}\), where \(h = 6.626 \times 10^{-34} \, \text{Js}\) and \(c = 3 \times 10^8 \, \text{m/s}\):
\[\lambda = \frac{hc}{E} = \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{0.05 \times 20 \times 10^3 \times 1.602 \times 10^{-19}} \approx 6.24 \, \text{nm}\]
Match Fibre with Application.\[\begin{array}{|l|l|} \hline \textbf{LIST I} & \textbf{LIST II} \\ \textbf{Fibre} & \textbf{Application} \\ \hline \hline \text{A. Silk fibre} & \text{I. Fire retardant} \\ \hline \text{B. Wool fibre} & \text{II. Directional lustre} \\ \hline \text{C. Nomex fibre} & \text{III. Bulletproof} \\ \hline \text{D. Kevlar fibre} & \text{IV. Thermal insulation} \\ \hline \end{array}\]