An overhead water tank of 7200 m3 capacity is being filled with water. The delivery of the pump filling the tank is 5/6th of the delivery of the pump discharging the same tank. As a result, 24 minutes more is needed to fill the tank than discharge it. Determine the delivery of the pump in filling the tank.
Let the delivery of the pump filling the tank = X m3/min ⇒ delivery of the pump discharging the tank = \(\frac{6}{5}\)X m3/min ⇒ \(\frac{7200}{X}-\frac{7200}{\frac{6}{5}X}=24\) ⇒ \(\frac{1200}{X}=24\) ⇒ X=50. So, the correct option is (D): 50 m3/min