


For v1,
\([\frac{1}{v_{1}}+\frac{1}{-10}=\frac{1}{12}=\frac{1}{v}=-\frac{1}{12}+\frac{1}{10}=\frac{-10+12}{120}=\frac{2}{120}=\frac{1}{60}]\)
v1=60cm
For v2,
\(\frac{1}{v_{1}}+\frac{1}{-80}=\frac{1}{10}=\frac{1}{v_{2}}=\frac{1}{10}-\frac{1}{80}=\frac{8-1}{80}=\frac{7}{80}\)
\(v_{2}=\frac{80}{7}cm\)
Reflection from M1
\(\frac{1}{v_{1}}+\frac{1}{-10}=\frac{1}{f_{1}}=\frac{1}{12}\)
\(\frac{1}{v}+\frac{1}{-10}=\frac{1}{f}=\frac{1}{12}=\frac{1}{v_{1}}+\frac{1}{-80}\)
\(\frac{1}{v_{2}}=\frac{1}{10}=\frac{1}{v}-\frac{1}{80}\)
For lens
\(v=\frac{uf}{u+f}=\frac{(-80)10}{-80+10}=\frac{80}{7}cm\)
For an image to form at S itself Ray after reflection from mirror 'M2 must be PARALLEL to the lens
L must form an image at the focus of 'M2'.
\(\frac{n}{7}=10+\frac{80}{7}=\frac{150}{7}\)
n=150
If l2 is formed at the pole of M1,
Then, \(\frac{n}{7}=\frac{80}{7}\)
n = 80
And if l2 is formed at the center of curvature of M1,
\(\frac{n}{7}=\frac{80}{7}+20\)
\(\therefore n=220\)
So, the answer is 80 or 150 or 220
A transparent block A having refractive index $ \mu_2 = 1.25 $ is surrounded by another medium of refractive index $ \mu_1 = 1.0 $ as shown in figure. A light ray is incident on the flat face of the block with incident angle $ \theta $ as shown in figure. What is the maximum value of $ \theta $ for which light suffers total internal reflection at the top surface of the block ?
The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ____. 
Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80
Let $ \mathbb{R} $ denote the set of all real numbers. Then the area of the region $$ \left\{ (x, y) \in \mathbb{R} \times \mathbb{R} : x > 0, y > \frac{1}{x},\ 5x - 4y - 1 > 0,\ 4x + 4y - 17 < 0 \right\} $$ is
As shown in the figures, a uniform rod $ OO' $ of length $ l $ is hinged at the point $ O $ and held in place vertically between two walls using two massless springs of the same spring constant. The springs are connected at the midpoint and at the top-end $ (O') $ of the rod, as shown in Fig. 1, and the rod is made to oscillate by a small angular displacement. The frequency of oscillation of the rod is $ f_1 $. On the other hand, if both the springs are connected at the midpoint of the rod, as shown in Fig. 2, and the rod is made to oscillate by a small angular displacement, then the frequency of oscillation is $ f_2 $. Ignoring gravity and assuming motion only in the plane of the diagram, the value of $\frac{f_1}{f_2}$ is:
Optics, deals with the determination of behaviour and the properties of light, along with its interactions with the matter and also with the instruments that are used to detect it.
Ray optics is also known as the geometrical optics and it is a branch of science which describes light propagation.
Reflection is the change in direction of light at an interface in-between two different media so that the wave-front returns into a medium from which it was originated.
Speed of light is the rate at which the light travels in free space.
A phenomenal change in image formed when the light is passed from one medium to another which is called Refraction.
Total Internal Reflection is the reflection of light when the light ray enters into a rarer medium from a denser medium and the angle of incidence is higher than the critical angle of incidence then that light ray will be reflected back to the denser medium.
Read More: Ray Optics and Optical Instruments