The mirror formula is given by:
\[
\frac{1}{f} = \frac{1}{v} + \frac{1}{u}
\]
where:
\( f \) is the focal length of the mirror,
\( v \) is the image distance,
\( u \) is the object distance.
Let the object be placed between the pole and the focus. So, \( u>f \).
Now, we rearrange the mirror formula:
\[
v = \frac{uf}{u - f}
\]
Using the new Cartesian sign convention, we get:
\[
v = \frac{(-u)(-f)}{-u - (-f)} = \frac{uf}{f - u}
\]
Since \( u>f \), the denominator is positive, and \( v \) will be positive, indicating that the image is virtual.
The magnification \( m \) is given by:
\[
m = -\frac{v}{u} = \frac{f}{f - u}
\]
Since \( m>1 \), the image is enlarged.
Thus, the image is virtual and enlarged.