At absolute zero temperature \( T = 0 \, {K} \), all the electrons in an intrinsic semiconductor are in the valence band and there are no free electrons in the conduction band.
Hence, it behaves like an insulator because no charge carriers are available for conduction.
Thus, the correct answer is (A).
Match the following types of nuclei with examples shown:
Let \( I = \int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \frac{\tan^2 x}{1+5^x} \, dx \). Then: