Question:
An infinitely long cylindrical water filament of radius \( R \) is surrounded by air. Assume water and air to be static. The pressure outside the filament is \( P_{out} \) and the pressure inside is \( P_{in} \). If \( \gamma \) is the surface tension of the water-air interface, then \( P_{in} - P_{out} \) is:
An infinitely long cylindrical water filament of radius \( R \) is surrounded by air. Assume water and air to be static. The pressure outside the filament is \( P_{out} \) and the pressure inside is \( P_{in} \). If \( \gamma \) is the surface tension of the water-air interface, then \( P_{in} - P_{out} \) is:
Updated On: Jul 17, 2024
- \(\frac{2\gamma}{R}\)
- 0
- \(\frac{\gamma}{R}\)
- \(\frac{4\gamma}{R}\)
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The Correct Option is C
Solution and Explanation
The correct option is (C) :\(\frac{\gamma}{R}\)
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