Step 1: Convert pH values to hydrogen ion concentrations.
\[ [H^+]_{\text{pH 2}} = 10^{-2} \, \text{mol/L}, \quad [H^+]_{\text{pH 8}} = 10^{-8} \, \text{mol/L} \]
Step 2: Calculate the volume-weighted average of the hydrogen ion concentration.
\[ [H^+]_{\text{avg}} = \frac{(2 \times 10^{-2}) + (3 \times 10^{-8})}{5} \approx 4 \times 10^{-3} \, \text{mol/L} \]
Step 3: Convert the average hydrogen ion concentration back to pH.
\[ \text{pH} = -\log(4 \times 10^{-3}) \approx 2.40 \]