The change in magnetic flux is related to the induced current by Faraday's Law of Induction:\( \mathcal{E} = - \frac{d\phi}{dt} \)
where \( \mathcal{E} \) is the induced emf, and
\( d\phi \) is the change in magnetic flux.
The induced emf is also related to the current and the resistance of the coil by Ohm's Law:
\( \mathcal{E} = I \cdot R \)
Substituting the given values:\( \mathcal{E} = 2 \times 100 = 200 \, \text{V} \)
Now, using Faraday's Law to find the change in flux: \( d\phi = \mathcal{E} \cdot dt = 200 \times 10^{-3} = 2 \times 10^{-3} \, \text{Wb} \)
When a bar magnet is pushed towards the coil, along its axis, as shown in the figure, the galvanometer pointer deflects towards X. When this magnet is pulled away from the coil, the galvanometer pointer
Two resistors are connected in a circuit loop of area 5 m\(^2\), as shown in the figure below. The circuit loop is placed on the \( x-y \) plane. When a time-varying magnetic flux, with flux-density \( B(t) = 0.5t \) (in Tesla), is applied along the positive \( z \)-axis, the magnitude of current \( I \) (in Amperes, rounded off to two decimal places) in the loop is (answer in Amperes).
List I | List II | ||
---|---|---|---|
A | Faraday's law | I | $\bigtriangledown -\bar{B}=0 $ |
B | Ampere's law | II | $\bigtriangledown -\bar{D}=\rho_v $ |
C | No monopole | III | $\bigtriangledown -\bar{H}=\bar{J}+\frac{\partial\bar{D} }{\partial t} $ |
D | Gauss's law | IV | $\bigtriangledown -\bar{E}=-\frac{\partial\bar{B} }{\partial t} $ |
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is
In an experiment to determine the figure of merit of a galvanometer by half deflection method, a student constructed the following circuit. He applied a resistance of \( 520 \, \Omega \) in \( R \). When \( K_1 \) is closed and \( K_2 \) is open, the deflection observed in the galvanometer is 20 div. When \( K_1 \) is also closed and a resistance of \( 90 \, \Omega \) is removed in \( S \), the deflection becomes 13 div. The resistance of galvanometer is nearly: