Step 1: Properties of an Ideal Transformer
An ideal transformer is a device with no energy losses. It operates on the principle of mutual induction and conserves energy.
Step 2: Power in an Ideal Transformer
In an ideal transformer, the input power (\(P_{in}\)) is equal to the output power (\(P_{out}\)). Mathematically, this is represented as:
\[ P_{in} = P_{out} \]
Step 3: Conclusion
Given an ideal transformer, the power output will always equal the power input, regardless of the turns ratio or input voltage.
Final Conclusion:
For an ideal transformer, output power equals input power.
For an ideal transformer, the power input is equal to the power output, as no energy is lost. The power in a transformer is given by: \[ P = VI \] Where \(P\) is the power, \(V\) is the voltage, and \(I\) is the current. The transformer equation relates the primary and secondary sides as: \[ \frac{V_p}{V_s} = \frac{N_p}{N_s} \] Where \(V_p\) and \(V_s\) are the voltages on the primary and secondary sides, and \(N_p\) and \(N_s\) are the number of turns on the primary and secondary coils, respectively. The turns ratio is \(N_p/N_s = 10\), and the primary voltage is \(V_p = 220 \, \text{V}\). Since an ideal transformer does not have losses, the power input is equal to the power output: \[ P_p = P_s \] Thus, the power output is equal to the power input.
A transformer of 100% efficiency has 200 turns in the primary and 40000 turns in the secondary. It is connected to a 220 V main supply and secondary feeds to a 100 K$\Omega$ resistance. The potential difference per turn is
The graph between variation of resistance of a wire as a function of its diameter keeping other parameters like length and temperature constant is
While determining the coefficient of viscosity of the given liquid, a spherical steel ball sinks by a distance \( x = 0.8 \, \text{m} \). The radius of the ball is \( 2.5 \times 10^{-3} \, \text{m} \). The time taken by the ball to sink in three trials are tabulated as shown: