Question:

An equation of a plane parallel to \(x-8y-9z=12\) is

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To be parallel: keep the \(x,y,z\) coefficients the same; change only the constant term.
  • \(x+8y+9z=12\)
  • \(x-8y-9z=2023\)
  • \(8x-y-9z=12\)
  • \(x-9y-8z=12\)
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The Correct Option is B

Solution and Explanation

Parallel planes have the same normal vector, so the coefficients of \(x,y,z\) must be proportional (here exactly the same). Only the constant may differ. Thus the family: \(x-8y-9z=d\) with any \(d\neq12\). Option (B) fits.
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