An energy-meter having a meter constant of 1200 rev/kWh is found to make 5 revolutions in 75s. The load power is:
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Use the meter constant and the number of revolutions to calculate the load power using the formula:
\(\text{Power} = \frac{\text{Revolutions} \times \text{Meter Constant}}{\text{Time}}\).
The power consumed is calculated using the meter constant and the number of revolutions made:
\[
\text{Power} = \frac{\text{Revolutions} \times \text{Meter Constant}}{\text{Time}} = \frac{5 \times 1200}{75} = 200 \, \text{W}
\]
Thus, the load power is 200 W.
Thus, the correct answer is 200 W.