Question

An energy-meter having a meter constant of 1200 rev/kWh is found to make 5 revolutions in 75s. The load power is:

• A. 500 W
• B. 100 W
• C. 200 W
• D. 1000 W

Hint:

Use the meter constant and the number of revolutions to calculate the load power using the formula: \(\text{Power} = \frac{\text{Revolutions} \times \text{Meter Constant}}{\text{Time}}\).

Answer 1

The Correct Option is C

The power consumed is calculated using the meter constant and the number of revolutions made: \[ \text{Power} = \frac{\text{Revolutions} \times \text{Meter Constant}}{\text{Time}} = \frac{5 \times 1200}{75} = 200 \, \text{W} \] Thus, the load power is 200 W. Thus, the correct answer is 200 W.