An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. Its final velocity will be
- $\sqrt {\frac {2eV}{m}} $
- $\sqrt {\frac {eV}{m}} $
- $\frac {eV}{2m} $
- $\frac {eV}{m} .$
The Correct Option is A
Solution and Explanation
$\frac {1}{2}\times mv^2=eV $
or final velocity of electron (v) $= \sqrt {\frac {2eV}{m}}. $
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