To determine the energy of an electron in the first excited state (\( n = 2 \)) within a one-dimensional (1D) box of length \( L = 1 \, \text{Å} \), we use the quantum mechanical model for a particle in a box. The energy levels are quantized and given by the formula: \[ E_n = \frac{n^2 h^2}{8mL^2} \] where:
Therefore, the energy of the electron in the first excited state is approximately 150.4 eV.
Wavefunctions and energies for a particle confined in a cubic box are \( \psi_{n_x,n_y,n_z} \) and \( E_{n_x,n_y,n_z} \), respectively. The functions \( \phi_1, \phi_2, \phi_3 \), and \( \phi_4 \) are written as linear combinations of \( \psi_{n_x,n_y,n_z} \). Among these functions, the eigenfunction(s) of the Hamiltonian operator for this particle is/are \[ \phi_1 = \frac{1}{\sqrt{2}} \psi_{1,4,1} - \frac{1}{\sqrt{2}} \psi_{2,2,3} \] \[ \phi_2 = \frac{1}{\sqrt{2}} \psi_{1,5,1} + \frac{1}{\sqrt{2}} \psi_{3,3,3} \] \[ \phi_3 = \frac{1}{\sqrt{2}} \psi_{1,3,8} + \frac{1}{\sqrt{2}} \psi_{3,8,1} \] \[ \phi_4 = \frac{1}{2} \psi_{3,3,1} + \frac{\sqrt{3}}{2} \psi_{2,4,1} \]
The correct option with regard to the following statements is
(a) Time-independent Schrödinger equation can be exactly solved for Be\(^{2+}\).
(b) For a particle confined in a one-dimensional box of length \( l \) with infinite potential barriers, the trial variation function \( \phi = \left[ \left( \frac{3}{l^3} \right)^{1/2} x \right] \) is not an acceptable trial wavefunction for \( 0 \le x \le l \).
(c) Wavefunctions for system of Fermions must be anti-symmetric with respect to exchange of any two Fermions in the system.
(d) Born-Oppenheimer approximation can be used to separate the vibrational and rotational motion of a molecule.