The power consumed by a device is related to the voltage applied and the resistance of the device.
The formula for power is:
\(P=\frac{V^2}{R}\).
The resistance R of the bulb can be found using the rated voltage and power of the bulb, which are 200 V and 100 W, respectively.
We use the formula
\(R = \frac{V_{\text{rated}}^2}{P_{\text{rated}}} = \frac{200^2}{100} = 400 \, \Omega\)
Now, we calculate the power consumed when the voltage applied is 160 V using the same formula:
\(P = \frac{160^2}{400} = \frac{25600}{400} = 64 \, W\)
Thus, the power consumed by the bulb when connected to a 160 V power supply is 64 W.
Given bulb ratings: 200 V, 100 W
First, calculate the resistance of the bulb:
P = V²/R ⇒ R = V²/P
R = (200)²/100 = 400 Ω
When connected to 160 V supply:
Pactual = Vsupply²/R
Pactual = (160)²/400 = 25600/400 = 64 W
The power consumed would be 64 W.
The Wheatstone bridge is an arrangement of four resistances, say \(R_1, R_2, R_3\), and \(R_4\). The null point condition is given by: