Question:

An electric bulb manufacturing company manufactures three types of electric bulbs A, B and C. In a room containing these three types of electric bulbs, it is known that 6% of type A electric bulbs are defective, 4% of type B electric bulbs are defective and 2% of type C electric bulbs are defective. An electric bulb is selected at random from a lot containing 50 type A electric bulbs,30 type B electric bulbs and 20 type C electric bulbs. The selected electric bulb is found to be defective. Then the probability that the selected electric bulb was type A is

Updated On: Jun 10, 2024
  • \(\frac{2}{23}\)
  • \(\frac{23}{500}\)
  • \(\frac{12}{23}\)
  • \(\frac{15}{23}\)
  • \(\frac{6}{115}\)
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The Correct Option is D

Solution and Explanation

The correct option is (D): \(\frac{15}{23}\)
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