Distance travelled = \( \frac{3}{4} \times 2 \pi R = \frac{3}{4} \times 2 \pi \times 40 = 60 \text{m} \)
Displacement = \( \sqrt{R^2 + R^2} = 40 \text{m} \)
A body of mass $100 \;g$ is moving in a circular path of radius $2\; m$ on a vertical plane as shown in the figure. The velocity of the body at point A is $10 m/s.$ The ratio of its kinetic energies at point B and C is: (Take acceleration due to gravity as $10 m/s^2$)

A sportsman runs around a circular track of radius $ r $ such that he traverses the path ABAB. The distance travelled and displacement, respectively, are:


Match List-I with List-II and select the correct option: 