Oxalic acid dihydrate $H_2C_2O_4.2H_2O:mw=126$
It is a dibasic acid, hence equivalent weight = 63
$\Rightarrow \, \, \, \, \, \, \, \, \, \, \, \, \, Normality=\frac{6.3}{63}\times \frac{1000}{250}=0.4 N$
$\Rightarrow \, \, \, \, \, \, \, \, \, \, \, \, \, N_1V_1 =N_2V_2$
$\Rightarrow \, \, \, \, \, \, \, \, \, \, \, \, 0.1 \times V_1 =0.4 \times \, 10$
Hence, $\, \, \, \, \, \, \, \, \, \, \, \, V_1 =40 mL$