Question:

An alkyl cyanide forms an amide when it is treated with

Updated On: Jun 14, 2022
  • $ H_2O + HCl $
  • $ NaOH + H_2O $
  • $ H_2O_2 + NaOH $
  • $ H_2SO_4 + H_2O $
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The Correct Option is D

Solution and Explanation

Amides are produced by alkyl cyanides by shaking them with cold cone. $HCl$ or by dissolving the nitriles in cone. $H_2SO_4$ and then pouring them into water.
$\underset{\text{alkyl cyanide}}{R - C \equiv N + H_2O} {->[\text{Cold conc}. HCl]} \underset {\text{amide}}{R - \overset{\underset{||}{O}}{C} - NH_2}$
$\underset{\text{ alkyl cyanide}}{R - C \equiv N} {->[\text{Dissolve in conc.} H_2SO_4][\text{and then pour in} H_2O]} \underset{\text{amide}}{R - \overset{\underset{||}{O}}{C} - NH_3}$
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Concepts Used:

Amines

Amine is a type of compound which is derived from ammonia (NH3). According to Organic chemistry, they are basically classified as the functional groups of the organic nitrogen compounds that contain nitrogen atoms with a lone pair.

Amine - Types

Primary Amines:

It is formed when one hydrogen atom in ammonia is substituted by an alkyl or aromatic group. Amino acids and methyl amine are the best examples that why aromatic amines include aniline.

Secondary Amines:

Amines that have two organic substitutes either alkyl or aryl ones or both and are bound to the nitrogen together with one hydrogen are termed as secondary amines. For Example, Dimethylamine.

Tertiary Amines:

Tertiary Amines are the amines where the nitrogen consists of three organic substitutes. For example, Trimethylamine and EDTA.