Question:
An alkene on reductive ozonolysis gives methanal as one of the products. Its structure is:
An alkene on reductive ozonolysis gives methanal as one of the products. Its structure is:
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Reductive ozonolysis of a terminal alkene produces methanal (formaldehyde) as one of the products.
Updated On: Jan 28, 2026
- CH\(_3\)CH\(_2\)CH\(_3\)
- CH\(_2\)CH=CH\(_2\)
- CH\(_2\)CH\(_3\)
- CH\(_2\)=CH\(_3\)
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The Correct Option is B
Solution and Explanation
Step 1: Understand reductive ozonolysis.
Reductive ozonolysis of alkenes results in the cleavage of the double bond, leading to the formation of aldehydes or ketones. If methanal (formaldehyde) is a product, the alkene must be a terminal alkene. Step 2: Identify the structure.
The correct structure of the alkene is \( \text{CH}_2\text{CH=CH}_2 \), which, on reductive ozonolysis, gives methanal as one of the products. Final Answer: \[ \boxed{\text{CH}_2\text{CH=CH}_2}. \]
Reductive ozonolysis of alkenes results in the cleavage of the double bond, leading to the formation of aldehydes or ketones. If methanal (formaldehyde) is a product, the alkene must be a terminal alkene. Step 2: Identify the structure.
The correct structure of the alkene is \( \text{CH}_2\text{CH=CH}_2 \), which, on reductive ozonolysis, gives methanal as one of the products. Final Answer: \[ \boxed{\text{CH}_2\text{CH=CH}_2}. \]
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