Question:

An alkali metal hydride $(NaH)$ reacts with diborane in $A$ to give a tetrahedral compound $B$ which is extensively used as reducing agent in organic synthesis. The compounds $A$ and $B$ respectively are

Updated On: Apr 2, 2024
  • $C_2H_6$ and $C_2H_5Na$
  • $CH_3COCH_3$ and $B_3N_3H_6$
  • $C_6H_6$ and $NaBH_4$
  • $(C_2H_5)_2O$ and $NaBH_4$
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The Correct Option is D

Solution and Explanation

Sodium hydride NaH reacts with diborane in diethylether to give tetrahydridoborates, i.e. sodium borohydride which is used as reducing agent in organic synthesis. $\underset{\text{Sodmm hydnde }}{{2NaH}} +\underset{\text{Diboran}}{{B_2H_6}} { ->[{Diethyl}][{ether}] A} \underset{\text{Sodium borohydride B}}{{2Na^+[BH_4]^-]}}$ A=diethyl ether $\left( C _{2} H _{5}\right)_{2} O$ B= Sodium borohydride $NaBH _{4}$
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Top Questions on p -Block Elements

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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: