An alkali metal hydride $(NaH)$ reacts with diborane in $A$ to give a tetrahedral compound $B$ which is extensively used as reducing agent in organic synthesis. The compounds $A$ and $B$ respectively are
Sodium hydride NaH reacts with diborane in diethylether to give tetrahydridoborates, i.e. sodium borohydride which is used as reducing agent in organic synthesis.
$\underset{\text{Sodmm hydnde }}{{2NaH}} +\underset{\text{Diboran}}{{B_2H_6}} { ->[{Diethyl}][{ether}] A} \underset{\text{Sodium borohydride B}}{{2Na^+[BH_4]^-]}}$
A=diethyl ether $\left( C _{2} H _{5}\right)_{2} O$ B= Sodium borohydride $NaBH _{4}$
P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.