Question:

An air bubble is trapped at point P (CP = 1.75 cm) in a spherical glass ball (n = 1.5) of radius 7 cm as shown in the figure. Find the nature and position of the image when viewed from side B. Show the image formation by drawing a ray diagram.
An air bubble is trapped at point P

Show Hint

When an object is placed inside a spherical surface, the image formed by the curved surface may be real and inverted depending on the object's distance from the center of the sphere. In this case, the negative sign indicates a real image formed on the opposite side.
Updated On: Jun 20, 2025
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

For light going from denser to rarer medium: \[ \frac{n_2}{-u} + \frac{n_1}{v} = \frac{n_1 - n_2}{R} \] Substitute the given values: \[ \frac{1.5}{8.75} + \frac{1}{v} = \frac{(1.5 - 1)}{-7} \] Simplifying: \[ \frac{1}{v} = \frac{0.5}{7} - \frac{1.5}{8.75} \] \[ \frac{1}{v} = -\frac{1}{10} \] Thus: \[ v = -10 \, \text{cm} \] The nature of the image is virtual.

Was this answer helpful?
0
0

Questions Asked in CBSE CLASS XII exam

View More Questions