

For light going from denser to rarer medium: \[ \frac{n_2}{-u} + \frac{n_1}{v} = \frac{n_1 - n_2}{R} \] Substitute the given values: \[ \frac{1.5}{8.75} + \frac{1}{v} = \frac{(1.5 - 1)}{-7} \] Simplifying: \[ \frac{1}{v} = \frac{0.5}{7} - \frac{1.5}{8.75} \] \[ \frac{1}{v} = -\frac{1}{10} \] Thus: \[ v = -10 \, \text{cm} \] The nature of the image is virtual.

Give reasons:
(i) The sky appears dark to passengers flying at very high altitudes.
At very high altitudes, passengers are above the atmosphere where there is less scattering of sunlight. As a result, they do not see the scattered blue light and the sky appears dark, similar to the condition experienced by astronauts in space.
(ii) 'Danger' signal lights are red in color.
मेले में बिताया एक दिन - लगभग 100 शब्दों में रचनात्मक लेख लिखिए