For light going from denser to rarer medium: \[ \frac{n_2}{-u} + \frac{n_1}{v} = \frac{n_1 - n_2}{R} \] Substitute the given values: \[ \frac{1.5}{8.75} + \frac{1}{v} = \frac{(1.5 - 1)}{-7} \] Simplifying: \[ \frac{1}{v} = \frac{0.5}{7} - \frac{1.5}{8.75} \] \[ \frac{1}{v} = -\frac{1}{10} \] Thus: \[ v = -10 \, \text{cm} \] The nature of the image is virtual.
Give reasons:
(i) The sky appears dark to passengers flying at very high altitudes.
At very high altitudes, passengers are above the atmosphere where there is less scattering of sunlight. As a result, they do not see the scattered blue light and the sky appears dark, similar to the condition experienced by astronauts in space.
(ii) 'Danger' signal lights are red in color.