An air bubble is trapped at point P (CP = 1.75 cm) in a spherical glass ball (n = 1.5) of radius 7 cm as shown in the figure. Find the nature and position of the image when viewed from side B. Show the image formation by drawing a ray diagram.
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Solution and Explanation
For light going from denser to rarer medium: \[ \frac{n_2}{-u} + \frac{n_1}{v} = \frac{n_1 - n_2}{R} \] Substitute the given values: \[ \frac{1.5}{8.75} + \frac{1}{v} = \frac{(1.5 - 1)}{-7} \] Simplifying: \[ \frac{1}{v} = \frac{0.5}{7} - \frac{1.5}{8.75} \] \[ \frac{1}{v} = -\frac{1}{10} \] Thus: \[ v = -10 \, \text{cm} \] The nature of the image is virtual.
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