Question

A glass slab (\( \mu = 1.5 \)) of thickness 6 cm is placed over a paper. The shift in the letters printed on the paper will be:

• A. 2 cm
• B. 1 cm
• C. 4 cm
• D. 3 cm

Hint:

The apparent shift due to a glass slab is given by \( \Delta x = t \left( 1 - \frac{1}{\mu} \right) \). Remember, the refractive index \( \mu \) reduces the apparent thickness of the object.

Answer 1

The Correct Option is A

When a glass slab is placed over an object, the apparent shift in position is related to the thickness of the slab and its refractive index. The formula for the apparent shift \( \Delta x \) is given by: \[ \Delta x = t \left( 1
- \frac{1}{\mu} \right) \] where:
- \( t \) is the thickness of the slab,
- \( \mu \) is the refractive index of the material. Given:
- \( t = 6 \, \text{cm} \),
- \( \mu = 1.5 \). Substituting the values: \[ \Delta x = 6 \left( 1
- \frac{1}{1.5} \right) = 6 \left( 1
- \frac{2}{3} \right) = 6 \times \frac{1}{3} = 2 \, \text{cm} \] Thus, the shift in the letters printed on the paper is 2 cm.