An air bubble in water ($ \mu = \frac{4}{3} $) is shown in the figure. The apparent depth of the image of the bubble in a plane mirror viewed by the observer is. 
The apparent depth of an object in a medium is given by the formula: \[ \text{Apparent depth} = \frac{\text{Real depth}}{\mu} \] where \( \mu \) is the refractive index of the medium. For the bubble in water, the real depth is the sum of the depth of the bubble (8 cm) and the distance from the surface to the bubble (24 cm), giving a total real depth of 24 cm.
Since the refractive index of water is \( \mu = \frac{4}{3} \), the apparent depth of the image in the plane mirror will be: \[ \text{Apparent depth} = \frac{24}{\frac{4}{3}} = 24 \, \text{cm} \]
Thus, the apparent depth of the image is 24 cm.

200 ml of an aqueous solution contains 3.6 g of Glucose and 1.2 g of Urea maintained at a temperature equal to 27$^{\circ}$C. What is the Osmotic pressure of the solution in atmosphere units?
Given Data R = 0.082 L atm K$^{-1}$ mol$^{-1}$
Molecular Formula: Glucose = C$_6$H$_{12}$O$_6$, Urea = NH$_2$CONH$_2$