Question:
Among the following, the conformation that corresponds to the most stable conformation of meso-butane-$2,3$-diol is
Among the following, the conformation that corresponds to the most stable conformation of meso-butane-$2,3$-diol is
Updated On: June 02, 2025
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Understanding the Structure of Meso-Butane-2,3-Diol
Meso-butane-2,3-diol is a compound with two hydroxyl groups (-OH) located on the second and third carbon atoms of a butane chain. It also contains two methyl groups (-Me) attached to the first and fourth carbon atoms.
Step 2: Analyzing the Conformation
The molecule can adopt different conformations based on the relative positioning of the substituents (-OH and -Me). The goal is to find the conformation with the lowest steric hindrance and torsional strain.
Step 3: Staggered Conformation
In a staggered conformation, the atoms or groups attached to the carbon atoms are positioned as far apart from each other as possible, minimizing repulsion. This is generally the most stable conformation for alkanes and related compounds.
Step 4: Anti Conformation of -OH and -Me Groups
In the most stable conformation, the bulky -OH and -Me groups should be positioned in an **anti** arrangement (opposite to each other), so they do not experience direct steric clashes. The -OH groups, as well as the -Me groups, are positioned as far apart as possible.
Step 5: Conclusion
The conformation that corresponds to the most stable conformation of meso-butane-2,3-diol is the one where both the -OH groups are anti to each other, and the -Me groups are also anti to each other, minimizing steric hindrance and maximizing stability.
Meso-butane-2,3-diol is a compound with two hydroxyl groups (-OH) located on the second and third carbon atoms of a butane chain. It also contains two methyl groups (-Me) attached to the first and fourth carbon atoms.
Step 2: Analyzing the Conformation
The molecule can adopt different conformations based on the relative positioning of the substituents (-OH and -Me). The goal is to find the conformation with the lowest steric hindrance and torsional strain.
Step 3: Staggered Conformation
In a staggered conformation, the atoms or groups attached to the carbon atoms are positioned as far apart from each other as possible, minimizing repulsion. This is generally the most stable conformation for alkanes and related compounds.
Step 4: Anti Conformation of -OH and -Me Groups
In the most stable conformation, the bulky -OH and -Me groups should be positioned in an **anti** arrangement (opposite to each other), so they do not experience direct steric clashes. The -OH groups, as well as the -Me groups, are positioned as far apart as possible.
Step 5: Conclusion
The conformation that corresponds to the most stable conformation of meso-butane-2,3-diol is the one where both the -OH groups are anti to each other, and the -Me groups are also anti to each other, minimizing steric hindrance and maximizing stability.
Meso compounds have a plane of symmetry. In case of butan-2, 3-diol, gauche form is the most stable due to intramolecular H-bonding.
The correct answer is option (B): 
Was this answer helpful?
0
0
Top Questions on The solid state
- A solution is prepared by adding 124 g of ethylene glycol (molar mass = 62 g mol\(^{-1}\)) to \( x \) g of water to get a 10 m solution. What is the value of \( x \) (in g)?
- AP EAPCET - 2025
- Chemistry
- The solid state
- A metal crystallizes in simple cubic lattice. The volume of one unit cell is \( 6.4 \times 10^{-7} \, \text{pm}^3 \). What is the radius of the metal atom in pm?
- AP EAPCET - 2025
- Chemistry
- The solid state
- The composition of a sample of wustite is \( \text{Fe}_{0.93} \text{O}_{1.00} \). Percentage of iron in the form of \( \text{Fe}^{3+} \) ion is nearly:
- AP EAPCET - 2025
- Chemistry
- The solid state
- An element (atomic weight = 250 u) crystallises in a simple cubic lattice. If the density of the unit cell is \( 7.2 \, \text{g cm}^{-3} \), what is the radius (in \( \text{\AA} \)) of the atom of the element? (\(N = 6.02 \times 10^{23} \, \text{mol}^{-1}\))
- AP EAPCET - 2025
- Chemistry
- The solid state
- The composition of a sample of wustite is \( \text{Fe}_{0.93} \text{O}_{1.00} \). Percentage of iron in the form of \( \text{Fe}^{3+} \) ion is nearly:
- AP EAPCET - 2025
- Chemistry
- The solid state
View More Questions
Questions Asked in JEE Advanced exam
- Let $ x_0 $ be the real number such that $ e^{x_0} + x_0 = 0 $. For a given real number $ \alpha $, define $$ g(x) = \frac{3xe^x + 3x - \alpha e^x - \alpha x}{3(e^x + 1)} $$ for all real numbers $ x $. Then which one of the following statements is TRUE?
- JEE Advanced - 2025
- Fundamental Theorem of Calculus
- At 25$^\circ$C, the concentration of H$^+$ ions in $ 1.00 \times 10^{-3} \, \text{M} $ aqueous solution of a weak monobasic acid having acid dissociation constant $ K_a = 4.00 \times 10^{-11} $ is $ X \times 10^{-7} \, \text{M} $. The value of $ X $ is ____. {Use: Ionic product of water $ K_w = 1.00 \times 10^{-14} $ at 25$^\circ$C
- JEE Advanced - 2025
- Ionic Equilibrium
- Consider the vectors $$ \vec{x} = \hat{i} + 2\hat{j} + 3\hat{k},\quad \vec{y} = 2\hat{i} + 3\hat{j} + \hat{k},\quad \vec{z} = 3\hat{i} + \hat{j} + 2\hat{k}. $$ For two distinct positive real numbers $ \alpha $ and $ \beta $, define $$ \vec{X} = \alpha \vec{x} + \beta \vec{y} - \vec{z},\quad \vec{Y} = \alpha \vec{y} + \beta \vec{z} - \vec{x},\quad \vec{Z} = \alpha \vec{z} + \beta \vec{x} - \vec{y}. $$ If the vectors $ \vec{X}, \vec{Y}, \vec{Z} $ lie in a plane, then the value of $ \alpha + \beta - 3 $ is ________.
Two identical concave mirrors each of focal length $ f $ are facing each other as shown. A glass slab of thickness $ t $ and refractive index $ n_0 $ is placed equidistant from both mirrors on the principal axis. A monochromatic point source $ S $ is placed at the center of the slab. For the image to be formed on $ S $ itself, which of the following distances between the two mirrors is/are correct:
- JEE Advanced - 2025
- Ray optics and optical instruments
- Let $$ \alpha = \frac{1}{\sin 60^\circ \sin 61^\circ} + \frac{1}{\sin 62^\circ \sin 63^\circ} + \cdots + \frac{1}{\sin 118^\circ \sin 119^\circ}. $$ Then the value of $$ \left( \frac{\csc 1^\circ}{\alpha} \right)^2 $$ is \rule{1cm}{0.15mm}.
- JEE Advanced - 2025
- Some Applications of Trigonometry
View More Questions
JEE Advanced Notification
Concepts Used:
Solid State
Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions.
Types of Solids:
Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;
- Amorphous solids behave the same as super cool liquids due to the arrangement of constituent particles in short-range order. They are isotropic and have a broad melting point (range is about greater than 5°C).
- Crystalline solids have a fixed shape and the constituent particles are arranged in a long-range order.