



To determine which compound has the lowest \(pK_a\) value, we need to consider the acidity of the protons marked in each compound. The \(pK_a\) value is inversely related to acidity—the lower the \(pK_a\), the more acidic the compound. Here's the step-by-step reasoning:
Upon examination, the compound depicted in the above image (compound with the correct tagged proton in the provided list) has features that contribute to a highly stable conjugate base due to the presence of electronegative atoms or extensive resonance stabilization. Hence, it exhibits the lowest \(pK_a\) value among the given options.
(A)

(B) 
(C) 
(D) 
The conjugate base of compound (C) is stabilized by extended conjugation.
Given below are two statements:
Statement I: D-(+)-glucose + D-(+)-fructose $\xrightarrow{H_2O}$ sucrose sucrose $\xrightarrow{\text{Hydrolysis}}$ D-(+)-glucose + D-(+)-fructose
Statement II: Invert sugar is formed during sucrose hydrolysis.
In the light of the above statements, choose the correct answer from the options given below -

The scientific study of matter’s properties and behaviour is known as chemistry. It is a natural science that studies the elements that makeup matter, as well as the compounds, made up of atoms, molecules, and ions: their composition, structure, qualities, and behaviour, as well as the changes that occur when they mix with other things.