Forces and tensions in the system: Apply Newton’s second law.
For the 2 kg block, along the incline:
\[ 2a = g \sin(30^\circ) = \frac{g}{2} \]
For the 4 kg mass:
\[ 4a = 2g \Rightarrow a = \frac{g}{3} \]
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: