To solve this question, we need to understand the nature of nucleophilic bimolecular substitution reactions (SN2) involving alkyl halides.
1. Understanding the SN2 Mechanism:
In the SN2 mechanism, the nucleophile attacks the carbon atom bonded to the leaving group from the opposite side of the leaving group. This results in the simultaneous displacement of the leaving group and the formation of a new bond with the nucleophile.
2. Inversion of Configuration:
During the attack by the nucleophile, there is a backside attack on the carbon. This causes the configuration at the chiral center to invert, meaning that if the molecule was initially in the "R" configuration, it will now be in the "S" configuration, and vice versa.
3. Conclusion:
Alkyl halides undergoing nucleophilic bimolecular substitution reactions (SN2) involve an inversion of configuration at the carbon center that is undergoing substitution.
Final Answer:
The correct option is (C) inversion of configuration.
A compound (A) with molecular formula $C_4H_9I$ which is a primary alkyl halide, reacts with alcoholic KOH to give compound (B). Compound (B) reacts with HI to give (C) which is an isomer of (A). When (A) reacts with Na metal in the presence of dry ether, it gives a compound (D), C8H18, which is different from the compound formed when n-butyl iodide reacts with sodium. Write the structures of A, (B), (C) and (D) when (A) reacts with alcoholic KOH.