Step 1: Acetylcholine is released by parasympathetic (vagal) nerves and acts on the heart pacemaker cells (SA node).
Step 2: It binds to muscarinic acetylcholine receptors (M2 receptors), which are a type of GPCR (G-protein coupled receptor).
Step 3: Binding activates Gi protein, which decreases cAMP levels and increases K\(^+\) conductance via GIRK channels. This hyperpolarises the cell, slowing depolarisation.
Step 4: As a result, heart rate is slowed. Options (B) and (D) are irrelevant (involving GABA receptors). Option (C) is incorrect because acetylcholine \textit{activates} G protein (Gi), not inhibits it.
Thus, the correct mechanism is (A).