Acetophenone when reacted with a base, $ C_6H_5ONa $, yields a stable compound which has the structure
Acetophenone Aldol Condensation Mechanism
When acetophenone (C6H5COCH3) reacts with sodium ethoxide (C2H5ONa):
C6H5COCH3 + C2H5O- → C6H5COCH2- + C2H5OH
The base abstracts an acidic α-hydrogen (pKa ≈ 20), forming a resonance-stabilized enolate anion.
The enolate attacks the carbonyl carbon of another acetophenone molecule:
C6H5COCH2- + C6H5COCH3 → C6H5COCH2CH(OH)C6H5
This forms a β-hydroxy ketone (aldol) intermediate.
Under basic conditions, the aldol undergoes elimination:
C6H5COCH2CH(OH)C6H5 → C6H5CH=CHCOC6H5 + H2O
Water is eliminated to form the α,β-unsaturated ketone (chalcone derivative).
Final Product: The stable α,β-unsaturated ketone (1,3-diphenylprop-2-en-1-one)
Therefore, the correct answer is A.
The aldol condensation is an important organic reaction where carbonyl compounds form new carbon-carbon bonds through nucleophilic addition and subsequent dehydration.
Reaction Mechanism:
1. Aldol Addition:
- Requirements: Compounds must have α-hydrogens (e.g., acetaldehyde, acetone)
- Base catalysis: Dilute NaOH or KOH generates the enolate nucleophile
- Key steps:
1. Deprotonation at α-carbon forms enolate ion
2. Enolate attacks carbonyl carbon of another molecule
3. Protonation yields β-hydroxy carbonyl compound
2. Dehydration:
- Conditions: Heating the aldol product
- Process: Elimination of water (E1cb mechanism)
- Result: Forms α,β-unsaturated carbonyl compound with new C=C bond
Key Features:
- Reversibility: Aldol addition is reversible, while dehydration drives reaction forward
- Stereochemistry: Often forms specific diastereomers in crossed aldol reactions
- Applications: Important for synthesizing complex molecules and natural products
Example Transformation:
Acetaldehyde → Aldol (3-hydroxybutanal) → Crotonaldehyde (but-2-enal)
A solid cylinder of mass 2 kg and radius 0.2 m is rotating about its own axis without friction with angular velocity 5 rad/s. A particle of mass 1 kg moving with a velocity of 5 m/s strikes the cylinder and sticks to it as shown in figure.
The angular velocity of the system after the particle sticks to it will be: