Question:

According to theoretical study of radiation from the same linear antenna, the power radiated is proportional to ( \( \lambda \) = wavelength )

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For antennas of fixed size, higher frequency (shorter wavelength) radiation leads to greater power emission.
Updated On: Jan 26, 2026
  • \( \lambda^{-2} \)
  • \( \lambda^{-1} \)
  • \( \lambda^{2} \)
  • \( \lambda \)
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The Correct Option is A

Solution and Explanation

Step 1: Recall radiation from a linear antenna.
For a linear (Hertzian) antenna of fixed length, the power radiated depends on the frequency of the emitted electromagnetic waves.
Step 2: Relation between power and frequency.
The radiated power is proportional to the square of frequency: \[ P \propto \nu^2 \]
Step 3: Use relation between frequency and wavelength.
\[ \nu = \frac{c}{\lambda} \Rightarrow \nu^2 \propto \frac{1}{\lambda^2} \]
Step 4: Substitute in power relation.
\[ P \propto \frac{1}{\lambda^2} \]
Step 5: Conclusion.
The power radiated is proportional to \( \lambda^{-2} \).
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