According to MO theory, the molecule which contain only π-Bonds between the atoms is
C2
N2
O2
B2
The correct option is: (A): C2.
Molecular Orbital (MO) theory is a model used to describe the electronic structure of molecules by considering the interactions between atomic orbitals to form molecular orbitals. In the context of π-bonds, we need to look at the arrangement of p-orbitals, which are typically involved in forming π-bonds.
A π-bond is formed by the overlap of two parallel p-orbitals. It's important to note that π-bonds are commonly found in molecules with multiple bonds, especially double and triple bonds.
The molecule C2 refers to a diatomic carbon molecule, which consists of two carbon atoms. Carbon has an atomic number of 6, and its electron configuration is 1s² 2s² 2p². When two carbon atoms come together to form a C2 molecule, their atomic orbitals combine to form molecular orbitals.
In C2, the atomic p-orbitals from each carbon atom overlap to create two molecular orbitals:
σ Molecular Orbital (σ MO): This molecular orbital is formed by the head-to-head overlap of the two 2p_z atomic orbitals. It's a bonding orbital and represents the σ-bond in the molecule.
π Molecular Orbital (π MO): This molecular orbital is formed by the parallel side-to-side overlap of the remaining 2p_x and 2p_y atomic orbitals. It's a bonding orbital and represents the π-bond in the molecule.
Since C2 molecule contains only π-bonds between the atoms (formed by the overlap of 2p_x and 2p_y orbitals), the answer "C2" is justified.
List - IMolecule | List - IIBond enthalpy (kJ mol-1) |
---|---|
(A) HCl | (I) 435.8 |
(B) N2 | (II) 498 |
(C) H2 | (III) 946.0 |
(D) O2 | (IV) 431.0 |
List-I (Compound / Species) | List-II (Shape / Geometry) |
---|---|
(A) \(SF_4\) | (I) Tetrahedral |
(B) \(BrF_3\) | (II) Pyramidal |
(C) \(BrO_{3}^{-}\) | (III) See saw |
(D) \(NH^{+}_{4}\) | (IV) Bent T-shape |
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