Question:

$AB$ crystallizes in a body centred cubic lattice with edge length 'a' equal to $387 \,pm$. The distance between two oppositely charged ions in the lattices is

Updated On: Apr 24, 2024
  • 250 pm
  • 200 pm
  • 300 pm
  • 335 pm
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The Correct Option is D

Solution and Explanation

For $BCC$ lattice body diagonal $= a \sqrt{ 3}$ .
The distance between the two oppositely charged ions $ = \frac{a}{2} \sqrt{3}$
$ = \frac{387 \times 1.732}{2} = 335\, pm $
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Concepts Used:

Solid State

Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions. 

Solid State

Types of Solids:

Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;

  • Amorphous solids behave the same as super cool liquids due to the arrangement of constituent particles in short-range order. They are isotropic and have a broad melting point (range is about greater than 5°C).
  • Crystalline solids have a fixed shape and the constituent particles are arranged in a long-range order.